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132514012535 = 5121123218809
BaseRepresentation
bin111101101101001110…
…0110101110101110111
3110200001010111022111012
41323122130311311313
54132342041400120
6140513123102435
712400551343652
oct1733234656567
9420033438435
10132514012535
1151220783a43
1221822811a1b
13c65a99c008
1465b1326899
1536a890b1c5
hex1eda735d77

132514012535 has 8 divisors (see below), whose sum is σ = 159018854640. Its totient is φ = 106009850304.

The previous prime is 132514012531. The next prime is 132514012537. The reversal of 132514012535 is 535210415231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132514012535 - 22 = 132514012531 is a prime.

It is a super-2 number, since 2×1325140125352 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132514012531) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 496211 + ... + 715019.

It is an arithmetic number, because the mean of its divisors is an integer number (19877356830).

Almost surely, 2132514012535 is an apocalyptic number.

132514012535 is a deficient number, since it is larger than the sum of its proper divisors (26504842105).

132514012535 is a wasteful number, since it uses less digits than its factorization.

132514012535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 339937.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 132514012535 its reverse (535210415231), we get a palindrome (667724427766).

The spelling of 132514012535 in words is "one hundred thirty-two billion, five hundred fourteen million, twelve thousand, five hundred thirty-five".

Divisors: 1 5 121123 218809 605615 1094045 26502802507 132514012535