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1325151056233 is a prime number
BaseRepresentation
bin10011010010001001001…
…010000111000101101001
311200200110001111111020101
4103102021022013011221
5133202402132244413
62452433242025401
7164511323062054
oct23221112070551
94620401444211
101325151056233
11470aa2251a84
121949a64a8261
1397c65a0c534
14481cda13a9b
152470bed4edd
hex13489287169

1325151056233 has 2 divisors, whose sum is σ = 1325151056234. Its totient is φ = 1325151056232.

The previous prime is 1325151056231. The next prime is 1325151056263. The reversal of 1325151056233 is 3326501515231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 984079872064 + 341071184169 = 992008^2 + 584013^2 .

It is a cyclic number.

It is not a de Polignac number, because 1325151056233 - 21 = 1325151056231 is a prime.

Together with 1325151056231, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1325151056192 and 1325151056201.

It is not a weakly prime, because it can be changed into another prime (1325151056231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662575528116 + 662575528117.

It is an arithmetic number, because the mean of its divisors is an integer number (662575528117).

Almost surely, 21325151056233 is an apocalyptic number.

It is an amenable number.

1325151056233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1325151056233 is an equidigital number, since it uses as much as digits as its factorization.

1325151056233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81000, while the sum is 37.

The spelling of 1325151056233 in words is "one trillion, three hundred twenty-five billion, one hundred fifty-one million, fifty-six thousand, two hundred thirty-three".