Base | Representation |
---|---|
bin | 10011010010001001001… |
… | …010010100010100101011 |
3 | 11200200110001121020121011 |
4 | 103102021022110110223 |
5 | 133202402141013233 |
6 | 2452433243124351 |
7 | 164511323406106 |
oct | 23221112242453 |
9 | 4620401536534 |
10 | 1325151110443 |
11 | 470aa2289786 |
12 | 1949a65136b7 |
13 | 97c65a2b104 |
14 | 481cda2973d |
15 | 2470bee60cd |
hex | 1348929452b |
1325151110443 has 2 divisors, whose sum is σ = 1325151110444. Its totient is φ = 1325151110442.
The previous prime is 1325151110429. The next prime is 1325151110447. The reversal of 1325151110443 is 3440111515231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1325151110443 - 213 = 1325151102251 is a prime.
It is not a weakly prime, because it can be changed into another prime (1325151110447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662575555221 + 662575555222.
It is an arithmetic number, because the mean of its divisors is an integer number (662575555222).
Almost surely, 21325151110443 is an apocalyptic number.
1325151110443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1325151110443 is an equidigital number, since it uses as much as digits as its factorization.
1325151110443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 1325151110443 its reverse (3440111515231), we get a palindrome (4765262625674).
The spelling of 1325151110443 in words is "one trillion, three hundred twenty-five billion, one hundred fifty-one million, one hundred ten thousand, four hundred forty-three".
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