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132520262234151 = 3114015765522247
BaseRepresentation
bin11110001000011011000111…
…001001111111000000100111
3122101012210221221000222212010
4132020123013021333000213
5114332202444112443101
61145502545032125303
736625162431221151
oct3610330711770047
9571183857028763
10132520262234151
1139252589264970
1212a43393836833
1358c37b7a7908c
1424a202ccd9ad1
15104c251e742d6
hex7886c727f027

132520262234151 has 8 divisors (see below), whose sum is σ = 192756745067904. Its totient is φ = 80315310444920.

The previous prime is 132520262234117. The next prime is 132520262234153. The reversal of 132520262234151 is 151432262025231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132520262234151 - 211 = 132520262232103 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132520262234153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2007882761091 + ... + 2007882761156.

It is an arithmetic number, because the mean of its divisors is an integer number (24094593133488).

Almost surely, 2132520262234151 is an apocalyptic number.

132520262234151 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

132520262234151 is a deficient number, since it is larger than the sum of its proper divisors (60236482833753).

132520262234151 is a wasteful number, since it uses less digits than its factorization.

132520262234151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4015765522261.

The product of its (nonzero) digits is 172800, while the sum is 39.

The spelling of 132520262234151 in words is "one hundred thirty-two trillion, five hundred twenty billion, two hundred sixty-two million, two hundred thirty-four thousand, one hundred fifty-one".

Divisors: 1 3 11 33 4015765522247 12047296566741 44173420744717 132520262234151