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132520433 is a prime number
BaseRepresentation
bin1111110011000…
…01100111110001
3100020100201212012
413321201213301
5232411123213
621052212305
73166255643
oct771414761
9306321765
10132520433
1168893621
123846a095
13215bba76
1413858893
15b97a4a8
hex7e619f1

132520433 has 2 divisors, whose sum is σ = 132520434. Its totient is φ = 132520432.

The previous prime is 132520393. The next prime is 132520447. The reversal of 132520433 is 334025231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119617969 + 12902464 = 10937^2 + 3592^2 .

It is a cyclic number.

It is not a de Polignac number, because 132520433 - 218 = 132258289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132520399 and 132520408.

It is not a weakly prime, because it can be changed into another prime (132520033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66260216 + 66260217.

It is an arithmetic number, because the mean of its divisors is an integer number (66260217).

Almost surely, 2132520433 is an apocalyptic number.

It is an amenable number.

132520433 is a deficient number, since it is larger than the sum of its proper divisors (1).

132520433 is an equidigital number, since it uses as much as digits as its factorization.

132520433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 132520433 is about 11511.7519518099. The cubic root of 132520433 is about 509.8326158375.

Adding to 132520433 its reverse (334025231), we get a palindrome (466545664).

The spelling of 132520433 in words is "one hundred thirty-two million, five hundred twenty thousand, four hundred thirty-three".