Base | Representation |
---|---|
bin | 11000101011110001… |
… | …11010010111000111 |
3 | 1021012120020120222220 |
4 | 30111320322113013 |
5 | 204120022030120 |
6 | 10030555223423 |
7 | 646254232032 |
oct | 142570722707 |
9 | 37176216886 |
10 | 13252142535 |
11 | 5690541915 |
12 | 269a147b73 |
13 | 13326b4678 |
14 | 8da042019 |
15 | 52865ab40 |
hex | 315e3a5c7 |
13252142535 has 8 divisors (see below), whose sum is σ = 21203428080. Its totient is φ = 7067809344.
The previous prime is 13252142521. The next prime is 13252142551. The reversal of 13252142535 is 53524125231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13252142535 - 25 = 13252142503 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13252142496 and 13252142505.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 441738070 + ... + 441738099.
It is an arithmetic number, because the mean of its divisors is an integer number (2650428510).
Almost surely, 213252142535 is an apocalyptic number.
13252142535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13252142535 is a deficient number, since it is larger than the sum of its proper divisors (7951285545).
13252142535 is an equidigital number, since it uses as much as digits as its factorization.
13252142535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 883476177.
The product of its digits is 36000, while the sum is 33.
Adding to 13252142535 its reverse (53524125231), we get a palindrome (66776267766).
The spelling of 13252142535 in words is "thirteen billion, two hundred fifty-two million, one hundred forty-two thousand, five hundred thirty-five".
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