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132525413051321 is a prime number
BaseRepresentation
bin11110001000011111111010…
…001010110010101110111001
3122101020022020220012121200102
4132020133322022302232321
5114332244021220120241
61145505200112045145
736625434164360633
oct3610377212625671
9571208226177612
10132525413051321
1139254791812064
1212a443908337b5
1358c4128c317a4
1424a239b019a53
15104c45426c39b
hex7887fa2b2bb9

132525413051321 has 2 divisors, whose sum is σ = 132525413051322. Its totient is φ = 132525413051320.

The previous prime is 132525413051303. The next prime is 132525413051323. The reversal of 132525413051321 is 123150314525231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131906051921296 + 619361130025 = 11485036^2 + 786995^2 .

It is a cyclic number.

It is not a de Polignac number, because 132525413051321 - 230 = 132524339309497 is a prime.

Together with 132525413051323, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132525413051323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66262706525660 + 66262706525661.

It is an arithmetic number, because the mean of its divisors is an integer number (66262706525661).

Almost surely, 2132525413051321 is an apocalyptic number.

It is an amenable number.

132525413051321 is a deficient number, since it is larger than the sum of its proper divisors (1).

132525413051321 is an equidigital number, since it uses as much as digits as its factorization.

132525413051321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108000, while the sum is 38.

Adding to 132525413051321 its reverse (123150314525231), we get a palindrome (255675727576552).

The spelling of 132525413051321 in words is "one hundred thirty-two trillion, five hundred twenty-five billion, four hundred thirteen million, fifty-one thousand, three hundred twenty-one".