Base | Representation |
---|---|
bin | 11110001000011111111010… |
… | …001010110010101110111011 |
3 | 122101020022020220012121200111 |
4 | 132020133322022302232323 |
5 | 114332244021220120243 |
6 | 1145505200112045151 |
7 | 36625434164360635 |
oct | 3610377212625673 |
9 | 571208226177614 |
10 | 132525413051323 |
11 | 39254791812066 |
12 | 12a443908337b7 |
13 | 58c4128c317a6 |
14 | 24a239b019a55 |
15 | 104c45426c39d |
hex | 7887fa2b2bbb |
132525413051323 has 2 divisors, whose sum is σ = 132525413051324. Its totient is φ = 132525413051322.
The previous prime is 132525413051321. The next prime is 132525413051341. The reversal of 132525413051323 is 323150314525231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132525413051323 - 21 = 132525413051321 is a prime.
Together with 132525413051321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (132525413051321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66262706525661 + 66262706525662.
It is an arithmetic number, because the mean of its divisors is an integer number (66262706525662).
Almost surely, 2132525413051323 is an apocalyptic number.
132525413051323 is a deficient number, since it is larger than the sum of its proper divisors (1).
132525413051323 is an equidigital number, since it uses as much as digits as its factorization.
132525413051323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324000, while the sum is 40.
Adding to 132525413051323 its reverse (323150314525231), we get a palindrome (455675727576554).
The spelling of 132525413051323 in words is "one hundred thirty-two trillion, five hundred twenty-five billion, four hundred thirteen million, fifty-one thousand, three hundred twenty-three".
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