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132525413051323 is a prime number
BaseRepresentation
bin11110001000011111111010…
…001010110010101110111011
3122101020022020220012121200111
4132020133322022302232323
5114332244021220120243
61145505200112045151
736625434164360635
oct3610377212625673
9571208226177614
10132525413051323
1139254791812066
1212a443908337b7
1358c4128c317a6
1424a239b019a55
15104c45426c39d
hex7887fa2b2bbb

132525413051323 has 2 divisors, whose sum is σ = 132525413051324. Its totient is φ = 132525413051322.

The previous prime is 132525413051321. The next prime is 132525413051341. The reversal of 132525413051323 is 323150314525231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132525413051323 - 21 = 132525413051321 is a prime.

Together with 132525413051321, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (132525413051321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66262706525661 + 66262706525662.

It is an arithmetic number, because the mean of its divisors is an integer number (66262706525662).

Almost surely, 2132525413051323 is an apocalyptic number.

132525413051323 is a deficient number, since it is larger than the sum of its proper divisors (1).

132525413051323 is an equidigital number, since it uses as much as digits as its factorization.

132525413051323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324000, while the sum is 40.

Adding to 132525413051323 its reverse (323150314525231), we get a palindrome (455675727576554).

The spelling of 132525413051323 in words is "one hundred thirty-two trillion, five hundred twenty-five billion, four hundred thirteen million, fifty-one thousand, three hundred twenty-three".