13253401154130 has 32 divisors (see below), whose sum is σ = 31815680957568. Its totient is φ = 3533404953600.

The previous prime is 13253401154099. The next prime is 13253401154209. The reversal of 13253401154130 is 3145110435231.

It is a junction number, because it is equal to n+sod(n) for n = 13253401154091 and 13253401154100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52080591 + ... + 52334450.

It is an arithmetic number, because the mean of its divisors is an integer number (994240029924).

Almost surely, 2^{13253401154130} is an apocalyptic number.

13253401154130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13253401154130 is an abundant number, since it is smaller than the sum of its proper divisors (18562279803438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13253401154130 is a wasteful number, since it uses less digits than its factorization.

13253401154130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104419282.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 13253401154130 its reverse (3145110435231), we get a palindrome (16398511589361).

The spelling of 13253401154130 in words is "thirteen trillion, two hundred fifty-three billion, four hundred one million, one hundred fifty-four thousand, one hundred thirty".