Base | Representation |
---|---|
bin | 10011010010011000001… |
… | …111100001101101100101 |
3 | 11200201002200201012000002 |
4 | 103102120033201231211 |
5 | 133203411424243440 |
6 | 2452514322231045 |
7 | 164520515153612 |
oct | 23223017415545 |
9 | 4621080635002 |
10 | 1325404134245 |
11 | 471112098264 |
12 | 194a571b5485 |
13 | 97ca628bc39 |
14 | 48215491509 |
15 | 24724326115 |
hex | 134983e1b65 |
1325404134245 has 8 divisors (see below), whose sum is σ = 1590877600800. Its totient is φ = 1060061547600.
The previous prime is 1325404134227. The next prime is 1325404134277. The reversal of 1325404134245 is 5424314045231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1325404134245 - 26 = 1325404134181 is a prime.
It is a super-2 number, since 2×13254041342452 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1325404134199 and 1325404134208.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32697695 + ... + 32738204.
It is an arithmetic number, because the mean of its divisors is an integer number (198859700100).
Almost surely, 21325404134245 is an apocalyptic number.
It is an amenable number.
1325404134245 is a deficient number, since it is larger than the sum of its proper divisors (265473466555).
1325404134245 is an equidigital number, since it uses as much as digits as its factorization.
1325404134245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65439955.
The product of its (nonzero) digits is 230400, while the sum is 38.
Adding to 1325404134245 its reverse (5424314045231), we get a palindrome (6749718179476).
The spelling of 1325404134245 in words is "one trillion, three hundred twenty-five billion, four hundred four million, one hundred thirty-four thousand, two hundred forty-five".
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