Base | Representation |
---|---|
bin | 11110001000110010010111… |
… | …100011011101110011100111 |
3 | 122101022012102012201020011011 |
4 | 132020302113203131303213 |
5 | 114333110114223130203 |
6 | 1145522234543123051 |
7 | 36630035305555666 |
oct | 3610622743356347 |
9 | 571265365636134 |
10 | 132545233411303 |
11 | 392621328a4959 |
12 | 12a481a25a3487 |
13 | 58c5c6733034b |
14 | 24a331b4dcddd |
15 | 104cc1435176d |
hex | 788c978ddce7 |
132545233411303 has 4 divisors (see below), whose sum is σ = 140342011847280. Its totient is φ = 124748454975328.
The previous prime is 132545233411243. The next prime is 132545233411321. The reversal of 132545233411303 is 303114332545231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132545233411303 - 217 = 132545233280231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132545233411333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3898389217963 + ... + 3898389217996.
It is an arithmetic number, because the mean of its divisors is an integer number (35085502961820).
Almost surely, 2132545233411303 is an apocalyptic number.
132545233411303 is a deficient number, since it is larger than the sum of its proper divisors (7796778435977).
132545233411303 is an equidigital number, since it uses as much as digits as its factorization.
132545233411303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7796778435976.
The product of its (nonzero) digits is 388800, while the sum is 40.
Adding to 132545233411303 its reverse (303114332545231), we get a palindrome (435659565956534).
The spelling of 132545233411303 in words is "one hundred thirty-two trillion, five hundred forty-five billion, two hundred thirty-three million, four hundred eleven thousand, three hundred three".
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