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13255340000 = 25547731297
BaseRepresentation
bin11000101100001010…
…00110111111100000
31021012210021001002112
430112011012333200
5204121331340000
610031151534452
7646323350060
oct142605067740
937183231075
1013255340000
115692326151
12269b22a428
131333263b66
148da6353a0
15528a8d235
hex316146fe0

13255340000 has 240 divisors, whose sum is σ = 37808372448. Its totient is φ = 4478976000.

The previous prime is 13255339997. The next prime is 13255340009. The reversal of 13255340000 is 4355231.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13255340009) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 10219352 + ... + 10220648.

Almost surely, 213255340000 is an apocalyptic number.

13255340000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13255340000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18904186224).

13255340000 is an abundant number, since it is smaller than the sum of its proper divisors (24553032448).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13255340000 is an equidigital number, since it uses as much as digits as its factorization.

13255340000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1407 (or 1384 counting only the distinct ones).

The product of its (nonzero) digits is 1800, while the sum is 23.

Adding to 13255340000 its reverse (4355231), we get a palindrome (13259695231).

The spelling of 13255340000 in words is "thirteen billion, two hundred fifty-five million, three hundred forty thousand".