132562019 has 2 divisors, whose sum is σ = 132562020. Its totient is φ = 132562018.

The previous prime is 132561997. The next prime is 132562021. The reversal of 132562019 is 910265231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132562019 is a prime.

It is a super-2 number, since 2×132562019² = 35145377762712722, which contains 22 as substring.

Together with 132562021, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 132561982 and 132562000.

It is not a weakly prime, because it can be changed into another prime (132562099) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66281009 + 66281010.

It is an arithmetic number, because the mean of its divisors is an integer number (66281010).

Almost surely, 2^132562019 is an apocalyptic number.

132562019 is a deficient number, since it is larger than the sum of its proper divisors (1).

132562019 is an equidigital number, since it uses as much as digits as its factorization.

132562019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 29.

The square root of 132562019 is about 11513.5580512716. The cubic root of 132562019 is about 509.8859401470.

The spelling of 132562019 in words is "one hundred thirty-two million, five hundred sixty-two thousand, nineteen".