Base | Representation |
---|---|
bin | 10011010011001010101… |
… | …111101010111010011111 |
3 | 11200210021202000211101201 |
4 | 103103022233222322133 |
5 | 133212130330440333 |
6 | 2453134350420331 |
7 | 164550514035442 |
oct | 23231257527237 |
9 | 4623252024351 |
10 | 1326251421343 |
11 | 471507396632 |
12 | 195052b016a7 |
13 | 980ac98a454 |
14 | 48295c09659 |
15 | 247738de17d |
hex | 134cabeae9f |
1326251421343 has 2 divisors, whose sum is σ = 1326251421344. Its totient is φ = 1326251421342.
The previous prime is 1326251421337. The next prime is 1326251421349. The reversal of 1326251421343 is 3431241526231.
It is a balanced prime because it is at equal distance from previous prime (1326251421337) and next prime (1326251421349).
It is a cyclic number.
It is not a de Polignac number, because 1326251421343 - 229 = 1325714550431 is a prime.
It is a super-2 number, since 2×13262514213432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1326251421349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 663125710671 + 663125710672.
It is an arithmetic number, because the mean of its divisors is an integer number (663125710672).
Almost surely, 21326251421343 is an apocalyptic number.
1326251421343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1326251421343 is an equidigital number, since it uses as much as digits as its factorization.
1326251421343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 103680, while the sum is 37.
Adding to 1326251421343 its reverse (3431241526231), we get a palindrome (4757492947574).
The spelling of 1326251421343 in words is "one trillion, three hundred twenty-six billion, two hundred fifty-one million, four hundred twenty-one thousand, three hundred forty-three".
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