Base | Representation |
---|---|
bin | 11110001010001011000111… |
… | …111111110110111110110111 |
3 | 122101122022101222021222011011 |
4 | 132022023013333312332313 |
5 | 114341140304033110320 |
6 | 1150034115404253051 |
7 | 36636651055503025 |
oct | 3612130777667667 |
9 | 571568358258134 |
10 | 132640535441335 |
11 | 39299598363649 |
12 | 12a6275ab41187 |
13 | 5901c4473ccac |
14 | 24a7b9c63d715 |
15 | 1050440de505a |
hex | 78a2c7ff6fb7 |
132640535441335 has 8 divisors (see below), whose sum is σ = 161777964538656. Its totient is φ = 104372880347040.
The previous prime is 132640535441269. The next prime is 132640535441339. The reversal of 132640535441335 is 533144535046231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132640535441335 - 215 = 132640535408567 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132640535441339) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 217443500419 + ... + 217443501028.
It is an arithmetic number, because the mean of its divisors is an integer number (20222245567332).
Almost surely, 2132640535441335 is an apocalyptic number.
132640535441335 is a deficient number, since it is larger than the sum of its proper divisors (29137429097321).
132640535441335 is an equidigital number, since it uses as much as digits as its factorization.
132640535441335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 434887001513.
The product of its (nonzero) digits is 7776000, while the sum is 49.
The spelling of 132640535441335 in words is "one hundred thirty-two trillion, six hundred forty billion, five hundred thirty-five million, four hundred forty-one thousand, three hundred thirty-five".
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