132653513131501 has 2 divisors, whose sum is σ = 132653513131502. Its totient is φ = 132653513131500.

The previous prime is 132653513131499. The next prime is 132653513131507. The reversal of 132653513131501 is 105131315356231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116892208188900 + 15761304942601 = 10811670^2 + 3970051^2 .

It is an emirp because it is prime and its reverse (105131315356231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132653513131501 - 2¹ = 132653513131499 is a prime.

It is a super-2 number, since 2×132653513131501² (a number of 29 digits) contains 22 as substring.

Together with 132653513131499, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132653513131507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66326756565750 + 66326756565751.

It is an arithmetic number, because the mean of its divisors is an integer number (66326756565751).

Almost surely, 2^{132653513131501} is an apocalyptic number.

It is an amenable number.

132653513131501 is a deficient number, since it is larger than the sum of its proper divisors (1).

132653513131501 is an equidigital number, since it uses as much as digits as its factorization.

132653513131501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 121500, while the sum is 40.

Adding to 132653513131501 its reverse (105131315356231), we get a palindrome (237784828487732).

The spelling of 132653513131501 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, five hundred thirteen million, one hundred thirty-one thousand, five hundred one".