Base | Representation |
---|---|
bin | 11110001010011001110100… |
… | …100110110001100001010111 |
3 | 122101200211010202121212112022 |
4 | 132022121310212301201113 |
5 | 114341420113423204443 |
6 | 1150045245333243355 |
7 | 36641050116114341 |
oct | 3612316446614127 |
9 | 571624122555468 |
10 | 132656316225623 |
11 | 392a5256191433 |
12 | 12a65823a9355b |
13 | 590358ac71788 |
14 | 24a885842a291 |
15 | 1050a66537e68 |
hex | 78a6749b1857 |
132656316225623 has 2 divisors, whose sum is σ = 132656316225624. Its totient is φ = 132656316225622.
The previous prime is 132656316225613. The next prime is 132656316225659. The reversal of 132656316225623 is 326522613656231.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132656316225623 - 210 = 132656316224599 is a prime.
It is a super-3 number, since 3×1326563162256233 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132656316225613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66328158112811 + 66328158112812.
It is an arithmetic number, because the mean of its divisors is an integer number (66328158112812).
Almost surely, 2132656316225623 is an apocalyptic number.
132656316225623 is a deficient number, since it is larger than the sum of its proper divisors (1).
132656316225623 is an equidigital number, since it uses as much as digits as its factorization.
132656316225623 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13996800, while the sum is 53.
The spelling of 132656316225623 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, three hundred sixteen million, two hundred twenty-five thousand, six hundred twenty-three".
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