Base | Representation |
---|---|
bin | 11110001010011001110101… |
… | …100000011001001111000100 |
3 | 122101200211011211001021112012 |
4 | 132022121311200121033010 |
5 | 114341420131310034000 |
6 | 1150045251033113352 |
7 | 36641050361365025 |
oct | 3612316540311704 |
9 | 571624154037465 |
10 | 132656331330500 |
11 | 392a52637689aa |
12 | 12a65828b58858 |
13 | 590359112ca83 |
14 | 24a885a43cc4c |
15 | 1050a67a1d735 |
hex | 78a6758193c4 |
132656331330500 has 48 divisors (see below), whose sum is σ = 291498859876224. Its totient is φ = 52736995490400.
The previous prime is 132656331330499. The next prime is 132656331330527. The reversal of 132656331330500 is 5033133656231.
It is a super-3 number, since 3×1326563313305003 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 813761024 + ... + 813924023.
It is an arithmetic number, because the mean of its divisors is an integer number (6072892914088).
Almost surely, 2132656331330500 is an apocalyptic number.
132656331330500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132656331330500 is an abundant number, since it is smaller than the sum of its proper divisors (158842528545724).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132656331330500 is a wasteful number, since it uses less digits than its factorization.
132656331330500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1627685229 (or 1627685217 counting only the distinct ones).
The product of its (nonzero) digits is 437400, while the sum is 41.
Adding to 132656331330500 its reverse (5033133656231), we get a palindrome (137689464986731).
The spelling of 132656331330500 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, three hundred thirty-one million, three hundred thirty thousand, five hundred".
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