Base | Representation |
---|---|
bin | 111101110010011101… |
… | …0011110010000010111 |
3 | 110200111100210122220221 |
4 | 1323210322132100113 |
5 | 4133222011134112 |
6 | 140542353335211 |
7 | 12405112405006 |
oct | 1734472362027 |
9 | 420440718827 |
10 | 132689552407 |
11 | 5130087a715 |
12 | 21871567507 |
13 | c688170a69 |
14 | 65ca77cc3d |
15 | 36b9032e07 |
hex | 1ee4e9e417 |
132689552407 has 12 divisors (see below), whose sum is σ = 140357062440. Its totient is φ = 125421980112.
The previous prime is 132689552381. The next prime is 132689552459. The reversal of 132689552407 is 704255986231.
It is not a de Polignac number, because 132689552407 - 211 = 132689550359 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132689592407) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 254932 + ... + 574777.
It is an arithmetic number, because the mean of its divisors is an integer number (11696421870).
It is a 2-persistent number, because it is pandigital, and so is 2⋅132689552407 = 265379104814, but 3⋅132689552407 = 398068657221 is not.
Almost surely, 2132689552407 is an apocalyptic number.
132689552407 is a deficient number, since it is larger than the sum of its proper divisors (7667510033).
132689552407 is an equidigital number, since it uses as much as digits as its factorization.
132689552407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 830190 (or 830171 counting only the distinct ones).
The product of its (nonzero) digits is 3628800, while the sum is 52.
The spelling of 132689552407 in words is "one hundred thirty-two billion, six hundred eighty-nine million, five hundred fifty-two thousand, four hundred seven".
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