Base | Representation |
---|---|
bin | 111101110011101111… |
… | …0010110100010111001 |
3 | 110200121100122021000022 |
4 | 1323213132112202321 |
5 | 4133314010344231 |
6 | 140550530220225 |
7 | 12406143511634 |
oct | 1734736264271 |
9 | 420540567008 |
10 | 132732512441 |
11 | 51323052181 |
12 | 21883a24675 |
13 | c6940329b9 |
14 | 65d2362c1b |
15 | 36bcbbbc7b |
hex | 1ee77968b9 |
132732512441 has 2 divisors, whose sum is σ = 132732512442. Its totient is φ = 132732512440.
The previous prime is 132732512401. The next prime is 132732512461. The reversal of 132732512441 is 144215237231.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 109690790416 + 23041722025 = 331196^2 + 151795^2 .
It is a cyclic number.
It is not a de Polignac number, because 132732512441 - 218 = 132732250297 is a prime.
It is not a weakly prime, because it can be changed into another prime (132732512401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66366256220 + 66366256221.
It is an arithmetic number, because the mean of its divisors is an integer number (66366256221).
Almost surely, 2132732512441 is an apocalyptic number.
It is an amenable number.
132732512441 is a deficient number, since it is larger than the sum of its proper divisors (1).
132732512441 is an equidigital number, since it uses as much as digits as its factorization.
132732512441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 40320, while the sum is 35.
Adding to 132732512441 its reverse (144215237231), we get a palindrome (276947749672).
The spelling of 132732512441 in words is "one hundred thirty-two billion, seven hundred thirty-two million, five hundred twelve thousand, four hundred forty-one".
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