Base | Representation |
---|---|
bin | 111101110110000111… |
… | …1011111010111100100 |
3 | 110200210221011011202002 |
4 | 1323230033133113210 |
5 | 4134000000040000 |
6 | 141002504504432 |
7 | 12411134434046 |
oct | 1735417372744 |
9 | 420727134662 |
10 | 132812502500 |
11 | 51364216967 |
12 | 218a677b118 |
13 | c6a778b6b2 |
14 | 65dcc25a96 |
15 | 36c4c1c8d5 |
hex | 1eec3df5e4 |
132812502500 has 30 divisors (see below), whose sum is σ = 290434385934. Its totient is φ = 53125000000.
The previous prime is 132812502497. The next prime is 132812502503. The reversal of 132812502500 is 5205218231.
It is an interprime number because it is at equal distance from previous prime (132812502497) and next prime (132812502503).
It can be written as a sum of positive squares in 5 ways, for example, as 73128058084 + 59684444416 = 270422^2 + 244304^2 .
It is not an unprimeable number, because it can be changed into a prime (132812502503) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 26560001 + ... + 26565000.
Almost surely, 2132812502500 is an apocalyptic number.
132812502500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132812502500 is an abundant number, since it is smaller than the sum of its proper divisors (157621883434).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132812502500 is an equidigital number, since it uses as much as digits as its factorization.
132812502500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53125025 (or 53125008 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 29.
The spelling of 132812502500 in words is "one hundred thirty-two billion, eight hundred twelve million, five hundred two thousand, five hundred".
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