Base | Representation |
---|---|
bin | 111101111000111001… |
… | …0111111111100011101 |
3 | 110201001102111221122012 |
4 | 1323301302333330131 |
5 | 4134142324301203 |
6 | 141020034201005 |
7 | 12413345533223 |
oct | 1736162777435 |
9 | 421042457565 |
10 | 132905697053 |
11 | 5140188a358 |
12 | 21911a23165 |
13 | c6c0b8b6bc |
14 | 660b364b13 |
15 | 36ccecabd8 |
hex | 1ef1cbff1d |
132905697053 has 4 divisors (see below), whose sum is σ = 139900733760. Its totient is φ = 125910660348.
The previous prime is 132905697031. The next prime is 132905697073. The reversal of 132905697053 is 350796509231.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 132905697053 - 28 = 132905696797 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132905696992 and 132905697010.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132905697013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3497518325 + ... + 3497518362.
It is an arithmetic number, because the mean of its divisors is an integer number (34975183440).
Almost surely, 2132905697053 is an apocalyptic number.
It is an amenable number.
132905697053 is a deficient number, since it is larger than the sum of its proper divisors (6995036707).
132905697053 is an equidigital number, since it uses as much as digits as its factorization.
132905697053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6995036706.
The product of its (nonzero) digits is 1530900, while the sum is 50.
The spelling of 132905697053 in words is "one hundred thirty-two billion, nine hundred five million, six hundred ninety-seven thousand, fifty-three".
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