Base | Representation |
---|---|
bin | 111101111011101101… |
… | …1000111110100000001 |
3 | 110201022000011011200011 |
4 | 1323313123013310001 |
5 | 4134341011213441 |
6 | 141033245424521 |
7 | 12415603130566 |
oct | 1736733076401 |
9 | 421260134604 |
10 | 133000101121 |
11 | 514500a9548 |
12 | 2193956b141 |
13 | c7075c30b4 |
14 | 6619ada86d |
15 | 36d6427581 |
hex | 1ef76c7d01 |
133000101121 has 2 divisors, whose sum is σ = 133000101122. Its totient is φ = 133000101120.
The previous prime is 133000101119. The next prime is 133000101127. The reversal of 133000101121 is 121101000331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 89030624400 + 43969476721 = 298380^2 + 209689^2 .
It is an emirp because it is prime and its reverse (121101000331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133000101121 - 21 = 133000101119 is a prime.
Together with 133000101119, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (133000101127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500050560 + 66500050561.
It is an arithmetic number, because the mean of its divisors is an integer number (66500050561).
Almost surely, 2133000101121 is an apocalyptic number.
It is an amenable number.
133000101121 is a deficient number, since it is larger than the sum of its proper divisors (1).
133000101121 is an equidigital number, since it uses as much as digits as its factorization.
133000101121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 133000101121 its reverse (121101000331), we get a palindrome (254101101452).
The spelling of 133000101121 in words is "one hundred thirty-three billion, one hundred one thousand, one hundred twenty-one".
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