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1330001221103 = 12791039875857
BaseRepresentation
bin10011010110101010010…
…000000001010111101111
311201010222001221101122022
4103112222100001113233
5133242320303033403
62454554421540355
7165042445564322
oct23265220012757
94633861841568
101330001221103
1147306101a6a5
1219591a8746bb
13985597c9289
144852dc307b9
15248e2be0d38
hex135aa4015ef

1330001221103 has 4 divisors (see below), whose sum is σ = 1331041098240. Its totient is φ = 1328961343968.

The previous prime is 1330001221069. The next prime is 1330001221121. The reversal of 1330001221103 is 3011221000331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1330001221103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330001421103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 519936650 + ... + 519939207.

It is an arithmetic number, because the mean of its divisors is an integer number (332760274560).

Almost surely, 21330001221103 is an apocalyptic number.

1330001221103 is a deficient number, since it is larger than the sum of its proper divisors (1039877137).

1330001221103 is a wasteful number, since it uses less digits than its factorization.

1330001221103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1039877136.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1330001221103 its reverse (3011221000331), we get a palindrome (4341222221434).

The spelling of 1330001221103 in words is "one trillion, three hundred thirty billion, one million, two hundred twenty-one thousand, one hundred three".

Divisors: 1 1279 1039875857 1330001221103