133000311010013 has 4 divisors (see below), whose sum is σ = 133000335710688. Its totient is φ = 133000286309340.

The previous prime is 133000311010001. The next prime is 133000311010033. The reversal of 133000311010013 is 310010113000331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133000311010013 - 2¹² = 133000311005917 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133000311009973 and 133000311010000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133000311010033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 453833 + ... + 16315838.

It is an arithmetic number, because the mean of its divisors is an integer number (33250083927672).

Almost surely, 2^{133000311010013} is an apocalyptic number.

It is an amenable number.

133000311010013 is a deficient number, since it is larger than the sum of its proper divisors (24700675).

133000311010013 is an equidigital number, since it uses as much as digits as its factorization.

133000311010013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24700674.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 133000311010013 its reverse (310010113000331), we get a palindrome (443010424010344).

The spelling of 133000311010013 in words is "one hundred thirty-three trillion, three hundred eleven million, ten thousand, thirteen".