1330005314041 has 4 divisors (see below), whose sum is σ = 1362444468084. Its totient is φ = 1297566160000.

The previous prime is 1330005313999. The next prime is 1330005314083. The reversal of 1330005314041 is 1404135000331.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1330005313999) and next prime (1330005314083).

It can be written as a sum of positive squares in 2 ways, for example, as 118198440000 + 1211806874041 = 343800^2 + 1100821^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330005314041 - 2²⁵ = 1329971759609 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330005313997 and 1330005314015.

It is not an unprimeable number, because it can be changed into a prime (1330005314741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16219576960 + ... + 16219577041.

It is an arithmetic number, because the mean of its divisors is an integer number (340611117021).

Almost surely, 2^{1330005314041} is an apocalyptic number.

It is an amenable number.

1330005314041 is a deficient number, since it is larger than the sum of its proper divisors (32439154043).

1330005314041 is an equidigital number, since it uses as much as digits as its factorization.

1330005314041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32439154042.

The product of its (nonzero) digits is 2160, while the sum is 25.

The spelling of 1330005314041 in words is "one trillion, three hundred thirty billion, five million, three hundred fourteen thousand, forty-one".