Base | Representation |
---|---|
bin | 10100011011101100111… |
… | …101111100100100001011 |
3 | 11222020022120201120120021 |
4 | 110123230331330210023 |
5 | 141001132030002311 |
6 | 2553014542041311 |
7 | 203305526401420 |
oct | 24335475744413 |
9 | 4866276646507 |
10 | 1404135000331 |
11 | 4a1543669238 |
12 | 1a8169b79237 |
13 | a25424a502b |
14 | 4bd63861d47 |
15 | 267d11a0171 |
hex | 146ecf7c90b |
1404135000331 has 16 divisors (see below), whose sum is σ = 1641739207680. Its totient is φ = 1175873866560.
The previous prime is 1404135000271. The next prime is 1404135000341. The reversal of 1404135000331 is 1330005314041.
It is a cyclic number.
It is not a de Polignac number, because 1404135000331 - 221 = 1404132903179 is a prime.
It is a super-2 number, since 2×14041350003312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1404135000296 and 1404135000305.
It is not an unprimeable number, because it can be changed into a prime (1404135000341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3549346 + ... + 3925063.
It is an arithmetic number, because the mean of its divisors is an integer number (102608700480).
Almost surely, 21404135000331 is an apocalyptic number.
1404135000331 is a deficient number, since it is larger than the sum of its proper divisors (237604207349).
1404135000331 is an equidigital number, since it uses as much as digits as its factorization.
1404135000331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7475034.
The product of its (nonzero) digits is 2160, while the sum is 25.
The spelling of 1404135000331 in words is "one trillion, four hundred four billion, one hundred thirty-five million, three hundred thirty-one", and thus it is an aban number.
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