1330010000147 has 2 divisors, whose sum is σ = 1330010000148. Its totient is φ = 1330010000146.

The previous prime is 1330010000131. The next prime is 1330010000149. The reversal of 1330010000147 is 7410000100331.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1330010000147 - 2⁴ = 1330010000131 is a prime.

Together with 1330010000149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1330010000149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665005000073 + 665005000074.

It is an arithmetic number, because the mean of its divisors is an integer number (665005000074).

Almost surely, 2^{1330010000147} is an apocalyptic number.

1330010000147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330010000147 is an equidigital number, since it uses as much as digits as its factorization.

1330010000147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 20.

Adding to 1330010000147 its reverse (7410000100331), we get a palindrome (8740010100478).

The spelling of 1330010000147 in words is "one trillion, three hundred thirty billion, ten million, one hundred forty-seven", and thus it is an aban number.