1330011101213 has 4 divisors (see below), whose sum is σ = 1330534112448. Its totient is φ = 1329488089980.

The previous prime is 1330011101201. The next prime is 1330011101219. The reversal of 1330011101213 is 3121011100331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1330011101213 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330011101191 and 1330011101200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330011101219) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261501803 + ... + 261506888.

It is an arithmetic number, because the mean of its divisors is an integer number (332633528112).

Almost surely, 2^{1330011101213} is an apocalyptic number.

It is an amenable number.

1330011101213 is a deficient number, since it is larger than the sum of its proper divisors (523011235).

1330011101213 is an equidigital number, since it uses as much as digits as its factorization.

1330011101213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 523011234.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1330011101213 its reverse (3121011100331), we get a palindrome (4451022201544).

The spelling of 1330011101213 in words is "one trillion, three hundred thirty billion, eleven million, one hundred one thousand, two hundred thirteen".