Base | Representation |
---|---|
bin | 111101111011101111… |
… | …0111110101000111001 |
3 | 110201022002001112111121 |
4 | 1323313132332220321 |
5 | 4134341241041441 |
6 | 141033323225241 |
7 | 12415614541243 |
oct | 1736736765071 |
9 | 421262045447 |
10 | 133001112121 |
11 | 5145072a089 |
12 | 21939978221 |
13 | c707888317 |
14 | 6619cc1093 |
15 | 36d6576dd1 |
hex | 1ef77bea39 |
133001112121 has 2 divisors, whose sum is σ = 133001112122. Its totient is φ = 133001112120.
The previous prime is 133001112119. The next prime is 133001112133. The reversal of 133001112121 is 121211100331.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 120555478521 + 12445633600 = 347211^2 + 111560^2 .
It is a cyclic number.
It is not a de Polignac number, because 133001112121 - 21 = 133001112119 is a prime.
Together with 133001112119, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 133001112095 and 133001112104.
It is not a weakly prime, because it can be changed into another prime (133001112421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500556060 + 66500556061.
It is an arithmetic number, because the mean of its divisors is an integer number (66500556061).
Almost surely, 2133001112121 is an apocalyptic number.
It is an amenable number.
133001112121 is a deficient number, since it is larger than the sum of its proper divisors (1).
133001112121 is an equidigital number, since it uses as much as digits as its factorization.
133001112121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 133001112121 its reverse (121211100331), we get a palindrome (254212212452).
The spelling of 133001112121 in words is "one hundred thirty-three billion, one million, one hundred twelve thousand, one hundred twenty-one".
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