133001113013 has 4 divisors (see below), whose sum is σ = 134986204320. Its totient is φ = 131016021708.

The previous prime is 133001112989. The next prime is 133001113019. The reversal of 133001113013 is 310311100331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133001113013 - 2⁶ = 133001112949 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133001112982 and 133001113000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133001113019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 992545553 + ... + 992545686.

It is an arithmetic number, because the mean of its divisors is an integer number (33746551080).

Almost surely, 2^133001113013 is an apocalyptic number.

It is an amenable number.

133001113013 is a deficient number, since it is larger than the sum of its proper divisors (1985091307).

133001113013 is an equidigital number, since it uses as much as digits as its factorization.

133001113013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1985091306.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 133001113013 its reverse (310311100331), we get a palindrome (443312213344).

The spelling of 133001113013 in words is "one hundred thirty-three billion, one million, one hundred thirteen thousand, thirteen".