Base | Representation |
---|---|
bin | 11110001111011010111100… |
… | …000110100101110010101001 |
3 | 122102220210010020211112112111 |
4 | 132033122330012211302221 |
5 | 114413042234430212301 |
6 | 1150511511243442321 |
7 | 40005004366345126 |
oct | 3617327406456251 |
9 | 572823106745474 |
10 | 133001113132201 |
11 | 39418501038676 |
12 | 12b0060b8263a1 |
13 | 5929c498b31a2 |
14 | 24bb406c5174d |
15 | 10599e68b9551 |
hex | 78f6bc1a5ca9 |
133001113132201 has 2 divisors, whose sum is σ = 133001113132202. Its totient is φ = 133001113132200.
The previous prime is 133001113132177. The next prime is 133001113132219. The reversal of 133001113132201 is 102231311100331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 81530877008025 + 51470236124176 = 9029445^2 + 7174276^2 .
It is a cyclic number.
It is not a de Polignac number, because 133001113132201 - 215 = 133001113099433 is a prime.
It is not a weakly prime, because it can be changed into another prime (133001113132291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500556566100 + 66500556566101.
It is an arithmetic number, because the mean of its divisors is an integer number (66500556566101).
Almost surely, 2133001113132201 is an apocalyptic number.
It is an amenable number.
133001113132201 is a deficient number, since it is larger than the sum of its proper divisors (1).
133001113132201 is an equidigital number, since it uses as much as digits as its factorization.
133001113132201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 133001113132201 its reverse (102231311100331), we get a palindrome (235232424232532).
The spelling of 133001113132201 in words is "one hundred thirty-three trillion, one billion, one hundred thirteen million, one hundred thirty-two thousand, two hundred one".
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