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1330012013333 is a prime number
BaseRepresentation
bin10011010110101010111…
…001001100001100010101
311201010222211020200210112
4103112222321030030111
5133242331033411313
62454555445132405
7165042636403463
oct23265271141425
94633884220715
101330012013333
11473067120aa3
121959223ba105
139855bb07603
144853143d833
15248e3b238a8
hex135aae4c315

1330012013333 has 2 divisors, whose sum is σ = 1330012013334. Its totient is φ = 1330012013332.

The previous prime is 1330012013167. The next prime is 1330012013353. The reversal of 1330012013333 is 3333102100331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1303599913009 + 26412100324 = 1141753^2 + 162518^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330012013333 - 232 = 1325717046037 is a prime.

It is a super-2 number, since 2×13300120133332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1330012013299 and 1330012013308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1330012013353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665006006666 + 665006006667.

It is an arithmetic number, because the mean of its divisors is an integer number (665006006667).

Almost surely, 21330012013333 is an apocalyptic number.

It is an amenable number.

1330012013333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330012013333 is an equidigital number, since it uses as much as digits as its factorization.

1330012013333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 1330012013333 its reverse (3333102100331), we get a palindrome (4663114113664).

The spelling of 1330012013333 in words is "one trillion, three hundred thirty billion, twelve million, thirteen thousand, three hundred thirty-three".