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133001222294119 is a prime number
BaseRepresentation
bin11110001111011011000010…
…100111000000101001100111
3122102220210101212020112112111
4132033123002213000221213
5114413043000401402434
61150511530143301451
740005010163246344
oct3617330247005147
9572823355215474
10133001222294119
1139418557717633
1212b006402aa887
135929c663b3c3a
1424bb4175497cb
151059a0127d964
hex78f6c29c0a67

133001222294119 has 2 divisors, whose sum is σ = 133001222294120. Its totient is φ = 133001222294118.

The previous prime is 133001222294117. The next prime is 133001222294173. The reversal of 133001222294119 is 911492222100331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133001222294119 - 21 = 133001222294117 is a prime.

It is a super-2 number, since 2×1330012222941192 (a number of 29 digits) contains 22 as substring.

Together with 133001222294117, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133001222294117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500611147059 + 66500611147060.

It is an arithmetic number, because the mean of its divisors is an integer number (66500611147060).

Almost surely, 2133001222294119 is an apocalyptic number.

133001222294119 is a deficient number, since it is larger than the sum of its proper divisors (1).

133001222294119 is an equidigital number, since it uses as much as digits as its factorization.

133001222294119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 40.

The spelling of 133001222294119 in words is "one hundred thirty-three trillion, one billion, two hundred twenty-two million, two hundred ninety-four thousand, one hundred nineteen".