Base | Representation |
---|---|
bin | 11110001111011011000010… |
… | …100111000000110100100011 |
3 | 122102220210101212020120111102 |
4 | 132033123002213000310203 |
5 | 114413043000401413234 |
6 | 1150511530143305015 |
7 | 40005010163251364 |
oct | 3617330247006443 |
9 | 572823355216442 |
10 | 133001222294819 |
11 | 3941855771810a |
12 | 12b006402ab16b |
13 | 5929c663b4358 |
14 | 24bb417549b6b |
15 | 1059a0127dc7e |
hex | 78f6c29c0d23 |
133001222294819 has 2 divisors, whose sum is σ = 133001222294820. Its totient is φ = 133001222294818.
The previous prime is 133001222294771. The next prime is 133001222294827. The reversal of 133001222294819 is 918492222100331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133001222294819 is a prime.
It is a super-3 number, since 3×1330012222948193 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (133001222294119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500611147409 + 66500611147410.
It is an arithmetic number, because the mean of its divisors is an integer number (66500611147410).
Almost surely, 2133001222294819 is an apocalyptic number.
133001222294819 is a deficient number, since it is larger than the sum of its proper divisors (1).
133001222294819 is an equidigital number, since it uses as much as digits as its factorization.
133001222294819 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 373248, while the sum is 47.
The spelling of 133001222294819 in words is "one hundred thirty-three trillion, one billion, two hundred twenty-two million, two hundred ninety-four thousand, eight hundred nineteen".
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