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133001222294819 is a prime number
BaseRepresentation
bin11110001111011011000010…
…100111000000110100100011
3122102220210101212020120111102
4132033123002213000310203
5114413043000401413234
61150511530143305015
740005010163251364
oct3617330247006443
9572823355216442
10133001222294819
113941855771810a
1212b006402ab16b
135929c663b4358
1424bb417549b6b
151059a0127dc7e
hex78f6c29c0d23

133001222294819 has 2 divisors, whose sum is σ = 133001222294820. Its totient is φ = 133001222294818.

The previous prime is 133001222294771. The next prime is 133001222294827. The reversal of 133001222294819 is 918492222100331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133001222294819 is a prime.

It is a super-3 number, since 3×1330012222948193 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (133001222294119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500611147409 + 66500611147410.

It is an arithmetic number, because the mean of its divisors is an integer number (66500611147410).

Almost surely, 2133001222294819 is an apocalyptic number.

133001222294819 is a deficient number, since it is larger than the sum of its proper divisors (1).

133001222294819 is an equidigital number, since it uses as much as digits as its factorization.

133001222294819 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 373248, while the sum is 47.

The spelling of 133001222294819 in words is "one hundred thirty-three trillion, one billion, two hundred twenty-two million, two hundred ninety-four thousand, eight hundred nineteen".