Base | Representation |
---|---|
bin | 11110001111011011000010… |
… | …101101100110000010001111 |
3 | 122102220210101222111020011010 |
4 | 132033123002231212002033 |
5 | 114413043001322120421 |
6 | 1150511530244300303 |
7 | 40005010214025366 |
oct | 3617330255460217 |
9 | 572823358436133 |
10 | 133001224020111 |
11 | 39418558696377 |
12 | 12b006409a1693 |
13 | 5929c66869735 |
14 | 24bb4178787dd |
15 | 1059a014c0076 |
hex | 78f6c2b6608f |
133001224020111 has 4 divisors (see below), whose sum is σ = 177334965360152. Its totient is φ = 88667482680072.
The previous prime is 133001224020097. The next prime is 133001224020113. The reversal of 133001224020111 is 111020422100331.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 133001224020111 - 210 = 133001224019087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133001224020113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22166870670016 + ... + 22166870670021.
It is an arithmetic number, because the mean of its divisors is an integer number (44333741340038).
Almost surely, 2133001224020111 is an apocalyptic number.
133001224020111 is a deficient number, since it is larger than the sum of its proper divisors (44333741340041).
133001224020111 is an equidigital number, since it uses as much as digits as its factorization.
133001224020111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44333741340040.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 133001224020111 its reverse (111020422100331), we get a palindrome (244021646120442).
The spelling of 133001224020111 in words is "one hundred thirty-three trillion, one billion, two hundred twenty-four million, twenty thousand, one hundred eleven".
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