Base | Representation |
---|---|
bin | 1100000110001010110100… |
… | …1011000010101100001111 |
3 | 1202002110221111221120010102 |
4 | 3001202231023002230033 |
5 | 3220402123232221031 |
6 | 44141554225401315 |
7 | 2541621321356501 |
oct | 301425513025417 |
9 | 52073844846112 |
10 | 13300124101391 |
11 | 426860735a226 |
12 | 15a97a079923b |
13 | 7562724189aa |
14 | 33da2d82dd71 |
15 | 180e77bab7cb |
hex | c18ad2c2b0f |
13300124101391 has 2 divisors, whose sum is σ = 13300124101392. Its totient is φ = 13300124101390.
The previous prime is 13300124101379. The next prime is 13300124101427. The reversal of 13300124101391 is 19310142100331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13300124101391 - 214 = 13300124085007 is a prime.
It is a super-2 number, since 2×133001241013912 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13300124101351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650062050695 + 6650062050696.
It is an arithmetic number, because the mean of its divisors is an integer number (6650062050696).
Almost surely, 213300124101391 is an apocalyptic number.
13300124101391 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300124101391 is an equidigital number, since it uses as much as digits as its factorization.
13300124101391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 29.
The spelling of 13300124101391 in words is "thirteen trillion, three hundred billion, one hundred twenty-four million, one hundred one thousand, three hundred ninety-one".
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