Base | Representation |
---|---|
bin | 1100000110001011001101… |
… | …1111100000111001100111 |
3 | 1202002111012220110102211012 |
4 | 3001202303133200321213 |
5 | 3220402332403200203 |
6 | 44142012534132435 |
7 | 2541624046534553 |
oct | 301426337407147 |
9 | 52074186412735 |
10 | 13300230131303 |
11 | 426866119a055 |
12 | 15a98101b111b |
13 | 75628b390c9b |
14 | 33da3d950863 |
15 | 180e82152bd8 |
hex | c18b37e0e67 |
13300230131303 has 2 divisors, whose sum is σ = 13300230131304. Its totient is φ = 13300230131302.
The previous prime is 13300230131291. The next prime is 13300230131311. The reversal of 13300230131303 is 30313103200331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13300230131303 is a prime.
It is a super-2 number, since 2×133002301313032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13300230131203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650115065651 + 6650115065652.
It is an arithmetic number, because the mean of its divisors is an integer number (6650115065652).
Almost surely, 213300230131303 is an apocalyptic number.
13300230131303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300230131303 is an equidigital number, since it uses as much as digits as its factorization.
13300230131303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 13300230131303 its reverse (30313103200331), we get a palindrome (43613333331634).
The spelling of 13300230131303 in words is "thirteen trillion, three hundred billion, two hundred thirty million, one hundred thirty-one thousand, three hundred three".
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