Base | Representation |
---|---|
bin | 10011010110101011100… |
… | …011100010000101101111 |
3 | 11201011000121010121202221 |
4 | 103112223203202011233 |
5 | 133242341404104241 |
6 | 2455000523100211 |
7 | 165043132633312 |
oct | 23265343420557 |
9 | 4634017117687 |
10 | 1330023113071 |
11 | 473072412434 |
12 | 195926071667 |
13 | 985611c28c3 |
14 | 48532acc979 |
15 | 248e4ab75d1 |
hex | 135ab8e216f |
1330023113071 has 2 divisors, whose sum is σ = 1330023113072. Its totient is φ = 1330023113070.
The previous prime is 1330023113039. The next prime is 1330023113191. The reversal of 1330023113071 is 1703113200331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1330023113071 - 25 = 1330023113039 is a prime.
It is a super-3 number, since 3×13300231130713 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330023813071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665011556535 + 665011556536.
It is an arithmetic number, because the mean of its divisors is an integer number (665011556536).
Almost surely, 21330023113071 is an apocalyptic number.
1330023113071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330023113071 is an equidigital number, since it uses as much as digits as its factorization.
1330023113071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 25.
The spelling of 1330023113071 in words is "one trillion, three hundred thirty billion, twenty-three million, one hundred thirteen thousand, seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •