Base | Representation |
---|---|
bin | 10011010110101011100… |
… | …011100010000111100111 |
3 | 11201011000121010121221101 |
4 | 103112223203202013213 |
5 | 133242341404110231 |
6 | 2455000523100531 |
7 | 165043132633543 |
oct | 23265343420747 |
9 | 4634017117841 |
10 | 1330023113191 |
11 | 473072412533 |
12 | 195926071747 |
13 | 985611c2986 |
14 | 48532acca23 |
15 | 248e4ab7661 |
hex | 135ab8e21e7 |
1330023113191 has 2 divisors, whose sum is σ = 1330023113192. Its totient is φ = 1330023113190.
The previous prime is 1330023113071. The next prime is 1330023113201. The reversal of 1330023113191 is 1913113200331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1330023113191 is a prime.
It is a super-2 number, since 2×13300231131912 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330023113491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665011556595 + 665011556596.
It is an arithmetic number, because the mean of its divisors is an integer number (665011556596).
Almost surely, 21330023113191 is an apocalyptic number.
1330023113191 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330023113191 is an equidigital number, since it uses as much as digits as its factorization.
1330023113191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 28.
The spelling of 1330023113191 in words is "one trillion, three hundred thirty billion, twenty-three million, one hundred thirteen thousand, one hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •