1330041312121 has 4 divisors (see below), whose sum is σ = 1335340281744. Its totient is φ = 1324742342500.

The previous prime is 1330041312101. The next prime is 1330041312169. The reversal of 1330041312121 is 1212131400331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1330041312121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330041312092 and 1330041312101.

It is not an unprimeable number, because it can be changed into a prime (1330041312101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2649484435 + ... + 2649484936.

It is an arithmetic number, because the mean of its divisors is an integer number (333835070436).

Almost surely, 2^{1330041312121} is an apocalyptic number.

It is an amenable number.

1330041312121 is a deficient number, since it is larger than the sum of its proper divisors (5298969623).

1330041312121 is an equidigital number, since it uses as much as digits as its factorization.

1330041312121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5298969622.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1330041312121 its reverse (1212131400331), we get a palindrome (2542172712452).

The spelling of 1330041312121 in words is "one trillion, three hundred thirty billion, forty-one million, three hundred twelve thousand, one hundred twenty-one".