Base | Representation |
---|---|
bin | 11000110001100011… |
… | …11010101010011101 |
3 | 1021022221111112120121 |
4 | 30120301322222131 |
5 | 204214430443123 |
6 | 10035450514541 |
7 | 650413402204 |
oct | 143061725235 |
9 | 37287445517 |
10 | 13300640413 |
11 | 5705957005 |
12 | 26b2435a51 |
13 | 133c765138 |
14 | 90266823b |
15 | 52ca3a75d |
hex | 318c7aa9d |
13300640413 has 2 divisors, whose sum is σ = 13300640414. Its totient is φ = 13300640412.
The previous prime is 13300640347. The next prime is 13300640443. The reversal of 13300640413 is 31404600331.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8515044729 + 4785595684 = 92277^2 + 69178^2 .
It is a cyclic number.
It is not a de Polignac number, because 13300640413 - 213 = 13300632221 is a prime.
It is a super-3 number, since 3×133006404133 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13300640443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650320206 + 6650320207.
It is an arithmetic number, because the mean of its divisors is an integer number (6650320207).
Almost surely, 213300640413 is an apocalyptic number.
It is an amenable number.
13300640413 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300640413 is an equidigital number, since it uses as much as digits as its factorization.
13300640413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
The spelling of 13300640413 in words is "thirteen billion, three hundred million, six hundred forty thousand, four hundred thirteen".
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