Base | Representation |
---|---|
bin | 1100000110001110001000… |
… | …0010010010110001100111 |
3 | 1202002120020022210200212201 |
4 | 3001203202002102301213 |
5 | 3220410432304003143 |
6 | 44142222230555331 |
7 | 2541652311032116 |
oct | 301434202226147 |
9 | 52076208720781 |
10 | 13301011000423 |
11 | 4268a21a53633 |
12 | 15a99a9808b47 |
13 | 7563840a6213 |
14 | 33dab5539c7d |
15 | 180eca99b64d |
hex | c18e2092c67 |
13301011000423 has 2 divisors, whose sum is σ = 13301011000424. Its totient is φ = 13301011000422.
The previous prime is 13301011000421. The next prime is 13301011000441. The reversal of 13301011000423 is 32400011010331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13301011000423 - 21 = 13301011000421 is a prime.
Together with 13301011000421, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13301011000423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13301011000421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650505500211 + 6650505500212.
It is an arithmetic number, because the mean of its divisors is an integer number (6650505500212).
Almost surely, 213301011000423 is an apocalyptic number.
13301011000423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301011000423 is an equidigital number, since it uses as much as digits as its factorization.
13301011000423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13301011000423 its reverse (32400011010331), we get a palindrome (45701022010754).
The spelling of 13301011000423 in words is "thirteen trillion, three hundred one billion, eleven million, four hundred twenty-three", and thus it is an aban number.
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