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133011123000 = 2335378971167
BaseRepresentation
bin111101111100000010…
…1001010101100111000
3110201022202220010211220
41323320011022230320
54134401321414000
6141034321552040
712416065614420
oct1737005125470
9421282803756
10133011123000
1151456347438
12219411a5620
13c709981b12
14661b369480
1536d73a31a0
hex1ef814ab38

133011123000 has 256 divisors, whose sum is σ = 479615385600. Its totient is φ = 30060518400.

The previous prime is 133011122899. The next prime is 133011123001. The reversal of 133011123000 is 321110331.

It is a super-2 number, since 2×1330111230002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133011123001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1833417 + ... + 1904583.

It is an arithmetic number, because the mean of its divisors is an integer number (1873497600).

Almost surely, 2133011123000 is an apocalyptic number.

133011123000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133011123000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (239807692800).

133011123000 is an abundant number, since it is smaller than the sum of its proper divisors (346604262600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133011123000 is a wasteful number, since it uses less digits than its factorization.

133011123000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71287 (or 71273 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 133011123000 its reverse (321110331), we get a palindrome (133332233331).

The spelling of 133011123000 in words is "one hundred thirty-three billion, eleven million, one hundred twenty-three thousand".