133011132320031 has 8 divisors (see below), whose sum is σ = 202683630201984. Its totient is φ = 76006361325720.

The previous prime is 133011132320009. The next prime is 133011132320047. The reversal of 133011132320031 is 130023231110331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 133011132320031 - 2²² = 133011128125727 is a prime.

It is a super-2 number, since 2×133011132320031² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133011132319983 and 133011132320010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133011132320051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3166931721885 + ... + 3166931721926.

It is an arithmetic number, because the mean of its divisors is an integer number (25335453775248).

Almost surely, 2^{133011132320031} is an apocalyptic number.

133011132320031 is a deficient number, since it is larger than the sum of its proper divisors (69672497881953).

133011132320031 is an equidigital number, since it uses as much as digits as its factorization.

133011132320031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6333863443821.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 133011132320031 its reverse (130023231110331), we get a palindrome (263034363430362).

The spelling of 133011132320031 in words is "one hundred thirty-three trillion, eleven billion, one hundred thirty-two million, three hundred twenty thousand, thirty-one".