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13301120420321 is a prime number
BaseRepresentation
bin1100000110001110100010…
…0011101100100111100001
31202002120111221200210202112
43001203220203230213201
53220411143311422241
644142241140125105
72541655110056426
oct301435043544741
952076457623675
1013301120420321
114268a787993a8
1215a9a1a396795
137563a0967516
1433dac5c9dd4d
15180ed53b21eb
hexc18e88ec9e1

13301120420321 has 2 divisors, whose sum is σ = 13301120420322. Its totient is φ = 13301120420320.

The previous prime is 13301120420303. The next prime is 13301120420323. The reversal of 13301120420321 is 12302402110331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9319343617600 + 3981776802721 = 3052760^2 + 1995439^2 .

It is a cyclic number.

It is not a de Polignac number, because 13301120420321 - 210 = 13301120419297 is a prime.

Together with 13301120420323, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13301120420323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650560210160 + 6650560210161.

It is an arithmetic number, because the mean of its divisors is an integer number (6650560210161).

Almost surely, 213301120420321 is an apocalyptic number.

It is an amenable number.

13301120420321 is a deficient number, since it is larger than the sum of its proper divisors (1).

13301120420321 is an equidigital number, since it uses as much as digits as its factorization.

13301120420321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13301120420321 its reverse (12302402110331), we get a palindrome (25603522530652).

The spelling of 13301120420321 in words is "thirteen trillion, three hundred one billion, one hundred twenty million, four hundred twenty thousand, three hundred twenty-one".