Base | Representation |
---|---|
bin | 1100000110001110100100… |
… | …1001110001000100000001 |
3 | 1202002120112122110211022022 |
4 | 3001203221021301010001 |
5 | 3220411203340300001 |
6 | 44142242134051225 |
7 | 2541655260642623 |
oct | 301435111610401 |
9 | 52076478424268 |
10 | 13301130400001 |
11 | 4268a83395274 |
12 | 15a9a217a9b15 |
13 | 7563a2a4ca62 |
14 | 33dac733ac13 |
15 | 180ed61d411b |
hex | c18e9271101 |
13301130400001 has 2 divisors, whose sum is σ = 13301130400002. Its totient is φ = 13301130400000.
The previous prime is 13301130399989. The next prime is 13301130400031. The reversal of 13301130400001 is 10000403110331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10807320927601 + 2493809472400 = 3287449^2 + 1579180^2 .
It is a cyclic number.
It is not a de Polignac number, because 13301130400001 - 234 = 13283950530817 is a prime.
It is not a weakly prime, because it can be changed into another prime (13301130400031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650565200000 + 6650565200001.
It is an arithmetic number, because the mean of its divisors is an integer number (6650565200001).
Almost surely, 213301130400001 is an apocalyptic number.
It is an amenable number.
13301130400001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301130400001 is an equidigital number, since it uses as much as digits as its factorization.
13301130400001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 13301130400001 its reverse (10000403110331), we get a palindrome (23301533510332).
The spelling of 13301130400001 in words is "thirteen trillion, three hundred one billion, one hundred thirty million, four hundred thousand, one".
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