13301130400031 has 2 divisors, whose sum is σ = 13301130400032. Its totient is φ = 13301130400030.

The previous prime is 13301130400001. The next prime is 13301130400067. The reversal of 13301130400031 is 13000403110331.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13301130400031 is a prime.

It is a super-2 number, since 2×13301130400031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13301130399976 and 13301130400012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13301130400001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650565200015 + 6650565200016.

It is an arithmetic number, because the mean of its divisors is an integer number (6650565200016).

Almost surely, 2^{13301130400031} is an apocalyptic number.

13301130400031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13301130400031 is an equidigital number, since it uses as much as digits as its factorization.

13301130400031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 13301130400031 its reverse (13000403110331), we get a palindrome (26301533510362).

The spelling of 13301130400031 in words is "thirteen trillion, three hundred one billion, one hundred thirty million, four hundred thousand, thirty-one".