Base | Representation |
---|---|
bin | 1100000110001110111111… |
… | …0100101110010010000111 |
3 | 1202002120211110002011022102 |
4 | 3001203233310232102013 |
5 | 3220411421013332403 |
6 | 44142301213022315 |
7 | 2541661120200146 |
oct | 301435764562207 |
9 | 52076743064272 |
10 | 13301242324103 |
11 | 4269030590528 |
12 | 15a9a5318499b |
13 | 7563bcca9b36 |
14 | 33dad815375d |
15 | 180ee0e41b88 |
hex | c18efd2e487 |
13301242324103 has 2 divisors, whose sum is σ = 13301242324104. Its totient is φ = 13301242324102.
The previous prime is 13301242324091. The next prime is 13301242324109. The reversal of 13301242324103 is 30142324210331.
It is a strong prime.
It is an emirp because it is prime and its reverse (30142324210331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13301242324103 - 24 = 13301242324087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13301242324109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650621162051 + 6650621162052.
It is an arithmetic number, because the mean of its divisors is an integer number (6650621162052).
Almost surely, 213301242324103 is an apocalyptic number.
13301242324103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301242324103 is an equidigital number, since it uses as much as digits as its factorization.
13301242324103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 13301242324103 its reverse (30142324210331), we get a palindrome (43443566534434).
The spelling of 13301242324103 in words is "thirteen trillion, three hundred one billion, two hundred forty-two million, three hundred twenty-four thousand, one hundred three".
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