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1330131000403 = 43123891291817
BaseRepresentation
bin10011010110110001111…
…111000101110001010011
311201011022010010212101001
4103112301333011301103
5133243102014003103
62455015335322431
7165045612645532
oct23266177056123
94634263125331
101330131000403
11473118300817
12195956220417
139857a66846a
1448543174319
15248ee2c901d
hex135b1fc5c53

1330131000403 has 8 divisors (see below), whose sum is σ = 1333776248640. Its totient is φ = 1326488341440.

The previous prime is 1330131000347. The next prime is 1330131000431. The reversal of 1330131000403 is 3040001310331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1330131000403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330131006403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 383751 + ... + 1675567.

It is an arithmetic number, because the mean of its divisors is an integer number (166722031080).

Almost surely, 21330131000403 is an apocalyptic number.

1330131000403 is a deficient number, since it is larger than the sum of its proper divisors (3645248237).

1330131000403 is a wasteful number, since it uses less digits than its factorization.

1330131000403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1294637.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 1330131000403 its reverse (3040001310331), we get a palindrome (4370132310734).

The spelling of 1330131000403 in words is "one trillion, three hundred thirty billion, one hundred thirty-one million, four hundred three", and thus it is an aban number.

Divisors: 1 431 2389 1029659 1291817 556773127 3086150813 1330131000403